#include  <stdio.h>
#include  <string.h>

char * fun (char  *s,  char *t )
{
  char   *p , *r, *a;
/************found************/
  a = NULL;
  while ( *s )
  {   p = s;   r = t;
      while ( *r )
/************found************/
        if ( *r == *p )
        { r++;  p++; };      
      if ( *r == '\0' ) a = s;
      s++;
  }
  return  a ;
}

main()
{
  char   s[100], t[100], *p;
  printf("\nPlease enter string S :"); scanf("%s", s );
  printf("\nPlease enter substring t :"); scanf("%s", t );
  p = fun( s, t );
  if ( p )  printf("\nThe result is :  %s\n", p);
  else      printf("\nNot found !\n" );
}

题目要求是  输入两个字符串  如s：ljdfjgl  t:fj 则输出fjgl  再如:输入s:fiufhgu  t:uf  则输出ufhgu  上面的程序只差一个语句就能完成，哪位大神第一个看出来  小弟把分全部给他！！